O=-16x^2+36x+61

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Solution for O=-16x^2+36x+61 equation:



=-16O^2+36O+61
We move all terms to the left:
-(-16O^2+36O+61)=0
We get rid of parentheses
16O^2-36O-61=0
a = 16; b = -36; c = -61;
Δ = b2-4ac
Δ = -362-4·16·(-61)
Δ = 5200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$O_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$O_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5200}=\sqrt{400*13}=\sqrt{400}*\sqrt{13}=20\sqrt{13}$
$O_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-20\sqrt{13}}{2*16}=\frac{36-20\sqrt{13}}{32} $
$O_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+20\sqrt{13}}{2*16}=\frac{36+20\sqrt{13}}{32} $

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